# How do you solve ln(x+4)=ln7?

Taking the $e$-xponential of both sides we get
${\cancel{e}}^{\cancel{\ln} \left(x + 4\right)} = {\cancel{e}}^{\cancel{\ln} 7}$
$x + 4 = 7$
Subtracting $4$ from both sides gives us our final answer of
$x = 3$