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How do you solve # ln x^3 = 2 ln 5 - 3 ln 2#?

1 Answer

Apr 21, 2016

#x=root3(25/8)=root3 25 / 2#

Explanation:

#lnx^3-2ln5+3ln2=0#
#lnx^3-ln5^2+ln2^3=0#
#lnx^3-ln25+ln8=0#
#ln((8x^3)/25)=0#
#e^0=(8x^3)/25#

#1=(8x^3)/25#

#25=8x^3#

#25/8=x^3#

#x=root3(25/8)=root3 25 / 2#

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