How do you solve #Ln(x+2)+ln(x-2)=3#?

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How do you solve #Ln(x+2)+ln(x-2)=3#?

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Answer 1 · 2016-03-08T18:21:58

#x~~4.9#

Explanation:

#ln(x+2)+ln(x-2)=3#
#ln[(x+2)(x-2)]=3#-> use property #log_bx+log_by=log_b(xy)#
#ln (x^2-4) =3#
#e^3=x^2-4#-> use definition #log_bx=n iffb^n=x#
#e^3+4=x^2#-> solve for x
#x=+-sqrt(e^3+4)#
#x~~4.9, x~~#-4.9

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How do you solve #Ln(x+2)+ln(x-2)=3#?

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