# How do you solve ln x=2?

$x = {e}^{2}$
$y = {\log}_{a} x \iff {a}^{y} = x$
Now ln is the natural logarithm and has base e, where $e \approx 2 , 71828$
$\therefore \ln x = 2 \implies {\log}_{e} x = 2$
$\therefore x = {e}^{2}$