How do you solve #Ln(x+1)-lnx=2#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Lucy Apr 27, 2018 #x=0.157# Explanation: #In(x+1)-In(x)=2# #In((x+1)/x)=2# #(x+1)/x=e^2# #x+1=xe^2# #x(1-e^2)=-1# #x=1/(e^2-1)# #x=0.157# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 9933 views around the world You can reuse this answer Creative Commons License