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How do you solve #Ln(x+1)-lnx=2#?

1 Answer

Apr 27, 2018

#x=0.157#

Explanation:

#In(x+1)-In(x)=2#

#In((x+1)/x)=2#

#(x+1)/x=e^2#

#x+1=xe^2#

#x(1-e^2)=-1#

#x=1/(e^2-1)#

#x=0.157#

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