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How do you solve #ln sqrt(x+1)=2#?

1 Answer

Dec 17, 2015

#x=e^4-1#

Explanation:

#lnsqrt(x+1)=2#

#thereforeln(x+1)^(1/2)=2#

#therefore 1/2ln(x+1)=2#

#thereforeln(x+1)=4#

#therefore(x+1)=e^4#

#thereforex=e^4-1#

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