Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #ln sqrt(x+1)=2#?

1 Answer

Dec 17, 2015

#x=e^4-1#

Explanation:

#lnsqrt(x+1)=2#

#thereforeln(x+1)^(1/2)=2#

#therefore 1/2ln(x+1)=2#

#thereforeln(x+1)=4#

#therefore(x+1)=e^4#

#thereforex=e^4-1#

Related questions

See all questions in Logarithmic Models

Impact of this question

6018 views around the world

You can reuse this answer
Creative Commons License