# How do you solve ln(7x+6)=1?

I found: $x = \frac{e - 6}{7}$
You can use the definition of log remembering that the base of $\ln$ is the irrational number $e$:
$\ln \left(7 x + 6\right) = 1$
$7 x + 6 = {e}^{1}$
$x = \frac{e - 6}{7}$