How do you solve ln(-4x-3) = ln12?

Mar 25, 2016

$x = - 3 \frac{3}{4}$

Explanation:

Solve $\ln \left(- 4 x - 3\right) = \ln 12$

We observe that on both sides we have $\ln$ of the numbers.
Therefore take $\text{Anti} \ln$ of both sides
cancel("Anti" ln)"of"cancel (ln) (-4x-3)=cancel("Anti" ln) "of" cancel(ln)12
$\implies \left(- 4 x - 3\right) = 12$
or $- 4 x = 12 + 3$, solving for $x$
$x = - \frac{15}{4} = - 3 \frac{3}{4}$