Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #ln 2x = -8#?

1 Answer

Aug 6, 2015

#x=(e^(-8))/2~~1.7*10^(-4)#

Explanation:

The relationship between the logartihm and exponential functions is:

#ln(x)=y harr e^y=x#

Therefore:

#ln(2x)=-8 rarr 2x=e^(-8) rarr x=(e^(-8))/2~~1.7*10^(-4)#

Related questions

See all questions in Logarithmic Models

Impact of this question

2440 views around the world

You can reuse this answer
Creative Commons License