How do you solve #k+(-6)=2#?

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Answer 1 · 2016-11-28T01:43:44

#k = 8#

To solve this problem first eliminate the parenthesis:

#k + (-6) = 2#

#k - 6 = 2#

Now we can add 6 to each side to isolate and solve for #k# while keeping the equation balanced:

#k - 6 + 6 = 2 + 6#

#k - 0 = 8#

#k = 8#