How do you solve #\frac { k + 1} { 3} = \frac { k - 2} { 6}#?

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Answer 1 · 2016-10-21T08:42:57

#k=-4#

#(k+1)/3=(k-2)/6#

Multiply both sides by 6 and simplify.

#6xx(k+1)/3=6xx(k-2)/6#

#2(k+1)=k-2#

#2k+2=k-2#

Subtract #k# from both sides.

#k+2=-2#

Subtract #2# from both sides.

#k=-2-2=-4#

#:.k=-4#