Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #\frac { 1} { 5} = 5^ { x - 1}#?

↳Redirected from "What covalent compounds are soluble in water?"

1 Answer

Dec 18, 2016

#x = 0#

Explanation:

#1/a^m = a^-m#

#1/5 = 1/5^1#

#=5^-1#

substitute power for #x - 1#:

#x - 1 = -1#

add 1:

#x = 0#

Related questions

See all questions in Logarithmic Models

Impact of this question

1164 views around the world

You can reuse this answer
Creative Commons License