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How do you solve #\frac { 1} { 5} = 5^ { x - 1}#?

1 Answer

Dec 18, 2016

#x = 0#

Explanation:

#1/a^m = a^-m#

#1/5 = 1/5^1#

#=5^-1#

substitute power for #x - 1#:

#x - 1 = -1#

add 1:

#x = 0#

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