How do you solve for x in #log(4x-1)=5#?

Related questions

• What is a logarithmic model?
• How do I use a logarithmic model to solve applications?
• What is the advantage of a logarithmic model?
• How does the Richter scale measure magnitude?
• What is the range of the Richter scale?
• How do you solve #9^(x-4)=81#?
• How do you solve #logx+log(x+15)=2#?
• How do you solve the equation #2 log4(x + 7)-log4(16) = 2#?
• How do you solve #2 log x^4 = 16#?
• How do you solve #2+log_3(2x+5)-log_3x=4#?