# How do you solve for x in log(4x-1)=5?

$x = \frac{100001}{4}$
$\log \left(4 x - 1\right) = 5 \implies 4 x - 1 = {10}^{5} \implies x = \frac{1}{4} \cdot \left(1 + {10}^{5}\right) = \frac{100001}{4}$