Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve for x in #log_3(x^(2)-2x)=1#?

1 Answer

Dec 31, 2015

#x_1=-1# and #x_2=3#

Explanation:

#log_3 (x^2-2x)=1#
#x^2-2x=3^1#
#x^2-2x-3=0#
#Delta = 4 +12 =16#
#x=(-b+-sqrt(Delta))/2=(2+-4)/2# => #x_1=-1# and #x_2=3#

Related questions

See all questions in Logarithmic Models

Impact of this question

3112 views around the world

You can reuse this answer
Creative Commons License