# How do you solve for x in Lnx^2=4?

Jul 11, 2016

x ± e^2

#### Explanation:

Taking the natural logarithm of both sides gives us

${\cancel{e}}^{\cancel{\ln} \left({x}^{2}\right)} = {e}^{4}$

${x}^{2} = {e}^{4}$

Taking the square root of both sides yields

x ± sqrt(e^4)

Simplifying further then gives us our result of

x ± e^2