How do you solve for x in $\frac{48}{125} = \frac{3 x}{25}$ $48/125=(3x)/25$ ?

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How do you solve for x in $\frac{48}{125} = \frac{3 x}{25}$ $48/125=(3x)/25$ ?

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Answer 1 · 2017-02-11T21:09:37

$x = \frac{16}{5}$ $x=16/5$

Explanation:

One way is to express the fraction on the right side with the equivalent denominator to the fraction on the left side.

$\Rightarrow \frac{3 x}{25} \times \frac{5}{5} = \frac{15 x}{125}$ $rArr(3x)/25xx5/5=(15x)/125$

We now have $\frac{48}{125} = \frac{15 x}{125}$ $48/125=(15x)/125$

Since the fractions are equal and have the same denominator, then their numerators must be equal.

$\Rightarrow 15 x = 48$ $rArr15x=48$

$\Rightarrow x = \frac{48}{15} = \frac{16}{5}$ $rArrx=48/15=16/5$

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How do you solve for x in $\frac{48}{125} = \frac{3 x}{25}$ $48/125=(3x)/25$ ?

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Explanation:

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How do you solve for x in 48125=3x2548/125=(3x)/25?

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Explanation:

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How do you solve for x in $\frac{48}{125} = \frac{3 x}{25}$ $48/125=(3x)/25$ ?