# How do you solve for x in 3^(2x) + 3^(x+1) - 4 = 0?

Apr 26, 2018

x=0

#### Explanation:

${3}^{2 x} + {3}^{x + 1} = 4$
${3}^{2 x} + {3}^{x + 1} = 1 + 3$
${3}^{2 x} + {3}^{x + 1} = {3}^{0} + {3}^{1}$

So:

$2 x = 0 \cap x + 1 = 1$

So:

$x = 0$