Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve for x in #3^(2x) + 3^(x+1) - 4 = 0#?

1 Answer

Apr 26, 2018

x=0

Explanation:

#3^(2x)+3^(x+1)=4#
#3^(2x)+3^(x+1)=1+3#
#3^(2x)+3^(x+1)=3^0+3^1#

So:

#2x=0 nn x+1=1#

So:

#x=0#

Related questions

See all questions in Logarithmic Models

Impact of this question

6588 views around the world

You can reuse this answer
Creative Commons License