How do you solve for x in # 1.76 = 2.718 ^ (.0093*x)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Bdub Apr 21, 2016 #x=ln1.76/(0.0093ln2.718) ~~60.79# Explanation: #ln 1.76=ln 2.718^(0.0093x)# #ln1.76=(0.0093x) ln2.718# #ln1.76/ln2.718=0.0093x # #x=ln1.76/(0.0093ln2.718) ~~60.79# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1014 views around the world You can reuse this answer Creative Commons License