# How do you solve for w in logw=1/2logx + logy?

##### 1 Answer
May 18, 2016

$w = {x}^{2} y$

#### Explanation:

$0 = \frac{1}{2} \log x + \log y - \log w$

$0 = \log {x}^{2} + \log y - \log w$

$0 = \log \left(\frac{{x}^{2} \times y}{w}\right)$

${10}^{0} = \frac{{x}^{2} y}{w}$

$1 = \frac{{x}^{2} y}{w}$

$w = {x}^{2} y$

Hopefully this helps!