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How do you solve for t #A= Ba^(ct)+D#?

1 Answer

May 7, 2018

#t=(A-D)/(Bclna)#

Explanation:

#A=Ba^(ct)+D#

#Ba^(ct)=A-D#

#a^(ct)=(A-D)/B#

#ctlna=(A-D)/B#

#t=(A-D)/(Bclna)#

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