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How do you solve for Kc in #7.2647 = -ln(Kc) #?

1 Answer

Mar 30, 2016

#K_c=e^(-7.2647)=0.0007#

Explanation:

#7.2647=-ln(K_c)#

#therefore ln(K_c)=-7.2647#

#thereforee^(ln(K_c))=e^(-7.2647)#

#therefore K_c=e^(-7.2647)=0.0007#.

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