How do you solve for c? 5(c+7) ≤ 15(c-3)

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Answer 1 · 2017-12-11T22:37:35

$c >= 8$

expand brackets:
$5(c+7) <= 15(c-3)$

$5c+35 <= 15c-45$

subtract $5c$

$35 <= 10c-45$

$10c-45>=35$

add $45:$

$10c >= 80$

divide by $10:$

$c >= 8$