How do you solve #e^x-9xe^x=0#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Jim H Sep 1, 2015 Factor and solve each factor equal to #0# Explanation: #e^x-9xe^x=0# #e^x(1-9x) = 0# #e^x = 0# #" "# or #" "# #1-9x =0# #e^x# is never #0# #1-9x =0# when # = =1/9# The only solution is #1/9# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2610 views around the world You can reuse this answer Creative Commons License