How do you solve #e^x − 1 − 5 = 5 #? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Trevor Ryan. Dec 25, 2015 #x=ln11# Explanation: #e^x-1-5=5# #thereforee^x=5+5+1=11# #therefore lne^x=ln11# #therefore xlne=ln11# #therefore x=ln11# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1782 views around the world You can reuse this answer Creative Commons License