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How do you solve #e^(4-2x) = 45#?

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Aug 11, 2018

#e^{4-2x}=45#

#ln(e^{4-2x})=ln 45#

#4-2x=ln45#

#-2x=ln45-4#

#2x=4-ln45#

#x=\frac{4-ln45}{2}#

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