# How do you solve #e^(2x) = 2e^x + 1 = 0#?

##### 1 Answer

May 19, 2018

See explanation.

#### Explanation:

If you substitute the expression

#e^(2x)-2e^x+1=0#

#t^2-2t+1=0#

#(t-1)^2=0#

#t=1#

Now we have to return to

#e^x=1=>e^x=e^0=>x=0#

Answer: **The equation has one solution #x=0#.**