# How do you solve e^(-2x+1)=14?

$\ln {e}^{- 2 x + 1} = \ln 14$
$\left(- 2 x + 1\right) \ln e = \ln 14$
$- 2 x + 1 = \ln 14$
$- 2 x = \ln 14 - 1$
$x = - \frac{\ln 14 - 1}{2}$