How do you solve #|d+5|>2#?

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Answer 1 · 2018-05-04T00:16:50

#-2 < d > -7#

#abs(d + 5) > 2#

#d + 5 > 2 or d + 5 > - 2#

#d + 5 > 2#

Subtract #5# from both sides;

#d + 5 - 5 > 2 - 5#

#d > -3#

Similarly..

#d + 5 > - 2#

Subtract #5# from both sides;

#d + 5 - 5 > - 2 - 5#

#d = > -7#

Therefore;

#-2 < d > -7#