How do you solve csc^2 (2x)=1?

1 Answer
Nghi N
Mar 6, 2018

#x = pi/4 + kpi#
#x = (3pi)/4 + kpi#

Explanation:

#csc^2 (2x) = 1/(sin^2 2x) = 1#
#sin^2 2x = 1#
#sin 2x = +- 1#
Using unit circle -->
a. sin 2x = 1
#2x = pi/2 + 2kpi#
#x = pi/4 + kpi#
b. sin 2x = - 1
#2x = (3pi)/2 + 2kpi#
#x = (3pi)/4 + kpi#

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