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How do you solve #cos(x+pi/3)+cos(x-pi/3)=1#?

1 Answer

A. S. Adikesavan

Aug 20, 2016

#x=2npi, n=0, +-1, +-2, +-3, ...#

Explanation:

Using #cos( A + B ) + co s( A - B ) = 2 cos A cos B#,

#2 cos x cos (pi/3)=1#.

As #cos(pi/3)=1/2#,

cos x = 1 = cos 0. Here 0 is the principal value #in [0. pi]#.

The general solution is #2npi+ 0= 2npi, n=0, +-1, +-2, +-3, ...#.

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