How do you solve $\frac{c - 8}{- 2} = \frac{11 - 4 c}{11}$ $(c-8)/-2=(11-4c)/11$ ?

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Answer 1 · 2018-05-08T13:55:36

$c = 22$ $c=22$

Multiply both sides by -22

$- 22 \times (\frac{c - 8}{- 2}) = - 22 \times (\frac{11 - 4 c}{11})$ $-22xx((c-8)/-2)=-22xx((11-4c)/11)$

Cancel

$11 \times (c - 8) = - 2 \times (11 - 4 c)$ $11xx(c-8)=-2xx(11-4c)$

multiply out

$11 c - 88 = - 22 + 8 c$ $11c-88=-22+8c$

Subtract $8 c$ $8c$ from both sides

$3 c - 88 = - 22$ $3c-88=-22$

Add 88 to both sides

$3 c = 66$ $3c=66$

Divide both sides by 3

$c = 22$ $c=22$

How do you solve c−8−2=11−4c11(c-8)/-2=(11-4c)/11?