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How do you solve #Ax=B# given #A=((1, 5))# and #B=(2)#?

1 Answer

Shwetank Mauria

Nov 30, 2016

Solution is #x=((k),((2-k)/5))#

Explanation:

As #A=((1, 5))# is a #1xx2# matrix and #B=(2)# is a #1xx1# matrix, as #Ax=B#, #x=X#, where #X# is a #2xx1# matrix.

Let #x# be #((x_1),(x_2))#

and hence #Ax=((1, 5))((x_1),(x_2))=(x_1+5x_2)#

But as #Ax=B=(2)#, we have #x_1+5x_2=2#

or #x_2=(2-x_1)/5# and if #x_1=k#

Solution is #x=((k),((2-k)/5))#

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