How do you solve and graph $x^2+3>2x$ ?

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Answer 1 · 2017-02-11T05:09:37

$x in (-oo, oo)$ .

Reorganizing,

$(x-1)^2+2>=2>0$ .

graph{x^2-2x+3 [-200, 200, -10, 190]}

The value of the expression #x^2-2x+3 is y-coordinate of the

parabola that is $>=2>0$ , for $x in (-oo, oo)$ .
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How do you solve and graph x^2+3>2xx^2+3>2x?