How do you solve and graph $x^2+25<10x$ ?

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Answer 1 · 2017-01-02T07:58:13

There is no real solution,

To solve $x^2+25-10x<0$ , we find that:

$x^2+25-10x=(x+-5)^2- or+ 10x to (x-5)^2>=0$

So, there is no real solution.

I tried in vain to invoke a Socratic graph that could illustrate my

conclusion.

How do you solve and graph x^2+25<10xx^2+25<10x?