How do you solve and graph #p-6>=3#?

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Answer 1 · 2017-03-20T09:21:33

See explanatom

Treat the manipulation the same way you would a normal equation.

Add 6 to both sides

#color(green)(p-6color(red)(+6)" ">=" "3color(red)(+6))#

But -6+6=0

#p+0" ">= 9#

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I know that they use the variable p but you would plot this the same way as you would #y>=9#

So the graph represents the equivalent of all the values of #y# that are greater than or equal to 9 no matter what value of #x#

As the 'p' may take on the value of 9 you use a solid line.
Tony B

Just for a moment, suppose #p# could not take on the value of 9 #(p>9)# then the line would need to be dotted to indicate this condition