How do you solve and graph abs(x+1)<0?

1 Answer
Rhys
Oct 29, 2017

No solutions
graph{abs(x+1) [-10, 10, -5, 5]}

Explanation:

We can note that |a| >= 0, |a| is never negative for all real a, so hence |x+1| is never negative, hence no solutions to |x+1|<0.

To sketch this graph, we can consider y = x+1
graph{y = x+1 [-10, 10, -5, 5]}

Then as we know |a| >= 0 for all real a, we just take the graph in the domain where the function is negative, and reflect in the x axis, so for x<-1 we make possitive, yielding;

graph{|x+1| [-10, 10, -5, 5]}

We can see clearly from this that |x+1| is never negative

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