How do you solve and graph $| x + 1 | < 0$ $abs(x+1)<0$ ?

Question

How do you solve and graph $| x + 1 | < 0$ $abs(x+1)<0$ ?

1 Answer

Impact of this question

2416 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-29T09:15:10

No solutions
graph{abs(x+1) [-10, 10, -5, 5]}

Explanation:

We can note that $| a | \geq 0, | a |$ $|a| >= 0, |a|$ is never negative for all real $a$ $a$ , so hence $| x + 1 |$ $|x+1|$ is never negative, hence no solutions to $| x + 1 | < 0$ $|x+1|<0$ .

To sketch this graph, we can consider $y = x + 1$ $y = x+1$
graph{y = x+1 [-10, 10, -5, 5]}

Then as we know $| a | \geq 0$ $|a| >= 0$ for all real a, we just take the graph in the domain where the function is negative, and reflect in the x axis, so for $x < - 1$ $x<-1$ we make possitive, yielding;

graph{|x+1| [-10, 10, -5, 5]}

We can see clearly from this that $| x + 1 |$ $|x+1|$ is never negative

Science

Math

Humanities

... and beyond

How do you solve and graph $| x + 1 | < 0$ $abs(x+1)<0$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve and graph |x+1|<0abs(x+1)<0?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve and graph $| x + 1 | < 0$ $abs(x+1)<0$ ?