How do you solve and graph #abs(1/4x+10)<18#?

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Answer 1 · 2017-07-14T16:50:53

#112 < x < 32# in conjunction with #|1/4 x+10| < y#

The #112 < x < 32# limits the domain (input).

This is another way of writing:

So we need the condition:

#-18<(1/4x+10)<18#

Subtract 10 from everything

#-28 < 1/4x< 8#

Multiply everything by 4

#-112 < x < 32#

Have a look at the example https://socratic.org/s/aGprwmLH
for the format of presentation #112< x <32#

What follows is for your understanding only. The teacher may not be expecting something like it

The shaded area is the feasible region for all #(x,y)#
Tony B