How do you solve and graph # |2x + 1| > -3#?

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Answer 1 · 2018-03-10T04:59:52

#x> -2 or x <1#

#|2x +1| > -3#

We know either: #2x+1> -3 or 2x + 1 < - (-3)#

Now let's solve the first possibility which is #2x + 1 > -3#

#2x + 1 > -3#

Add #-1# on both sides

#2x + 1 -1 > -3 - 1#

#2x > -4#

Divide both sides by #2#

#(2x)/2 > (-4)/2#

#x > -2#

Now let's solve the second possibility

#2x + 1 < - (-3)#

#2x + 1< 3#

Add #-1# on both sides

#2x + 1 - 1 < 3 -1#

#2x < 2#

#(2x)/2 < 2/2#

#x < 1#

Thus,

The answers are:

#x > -2 or x < 1#

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