How do you solve and find the value of $sin^-1(1/2)$ ?

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How do you solve and find the value of $sin^-1(1/2)$ ?

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Answer 1 · 2016-12-13T14:38:24

$pi/6 + 2kpi$
$(5pi)/6 + 2kpi$

Explanation:

$sin^-1 (1/2) --> arcsin (1/2)$
Trig table of special arcs gives -->
$sin x = 1/2$ --> arc $x = pi/6$
Unit circle gives another arc that has the same sin value (1/2) -->
arc $x = pi - pi/6 = (5pi)/6$
General answers:
$x = pi/6 + 2kpi$
$x = (5pi)/6 + 2kpi$

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How do you solve and find the value of $sin^-1(1/2)$ ?

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