How do you solve and find the value of #cos(arctan(3/5))#?
1 Answer
Dec 23, 2016
Explanation:
Let
Hence
and
=
#1/sectheta# =
#1/sqrt(sec^2theta)# =
#1/sqrt(1+tan^2theta)# =
#1/sqrt(1+(3/5)^2)# =
#1/sqrt(1+9/25)# =
#1/sqrt(34/25)# =
#sqrt(25/34)# =
#5/sqrt34#
