How do you solve and find the value of #cos^-1(sin^-1 90)#?

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How do you solve and find the value of #cos^-1(sin^-1 90)#?

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Answer 1 · 2017-11-08T03:10:01

One cannot evaluate #cos^-1(sin^-1 90)#, because #90# is outside the domain for the inverse sine function:

#theta = sin^-1(x); -1 <= x <= 1#

Also, please observe that the inverse sine function returns an angle with the units of either degrees or radians; this is incompatible with the argument of the inverse cosine function, which requires a unitless quantity.

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How do you solve and find the value of #cos^-1(sin^-1 90)#?

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