How do you solve #abs(x+6)<4#?
1 Answer
Jul 2, 2017
Explanation:
#"inequalities of the type " |x| < a#
#"always have solutions of the form " -a < x < a#
#rArr-4 < x+6 < 4#
#"subtract 6 from all 3 intervals"#
#-4-6 < xcancel(+6)cancel(-6) < 4-6#
#rArr-10 < x < -2" is the solution"#
