How do you solve #abs( x + 3) <2#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. Jun 28, 2016 #x< -1 and x> -5# In interval notation solution is #(-5, -1)# Explanation: #|x+3| < 2 ; x+3 < 2 and x+3 > -2 :. x< -1 and x> -5# In interval notation solution is # (-5, -1)#[Ans] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1176 views around the world You can reuse this answer Creative Commons License