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How do you solve #abs(x/3+1/4)>1/2#?

1 Answer

Apr 28, 2018

The answer #x>3/4# and #x<-9/4#

Explanation:

show the steps

#|x/3+1/4|>1/2#

First sol:

#x/3+1/4>1/2#

#x/3>1/4#

#x>3/4#

second sol:

#x/3+1/4<-1/2#

#x/3<-3/4#

#x<-9/4#

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