How do you solve #abs(x+ 1/3)=5/3#?

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How do you solve #abs(x+ 1/3)=5/3#?

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Answer 1 · 2018-05-28T03:27:04

# x = \frac{4}{3} # , # x =-2 #

Explanation:

Since # |x+\frac{1}{3}| = \frac{5}{3} # ,
# \pm (x+\frac{1}{3}) = \frac{5}{3} #
# x+\frac{1}{3} = 5/3, x+\frac{1}{3} = -5/3 #
# x = 4/3, x = -6/3 = -2 #

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How do you solve #abs(x+ 1/3)=5/3#?

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