# How do you solve abs(x+ 1/3)=5/3?

$x = \setminus \frac{4}{3}$ , $x = - 2$
Since $| x + \setminus \frac{1}{3} | = \setminus \frac{5}{3}$ ,
$\setminus \pm \left(x + \setminus \frac{1}{3}\right) = \setminus \frac{5}{3}$
$x + \setminus \frac{1}{3} = \frac{5}{3} , x + \setminus \frac{1}{3} = - \frac{5}{3}$
$x = \frac{4}{3} , x = - \frac{6}{3} = - 2$