How do you solve $| c - 3 | = 1$ $abs(c-3)=1$ ?

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How do you solve $| c - 3 | = 1$ $abs(c-3)=1$ ?

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Answer 1 · 2016-07-01T13:05:26

c = 4 or c = 2

Explanation:

To 'clear' the absolute value bars, we must express the equation in its 2 possible cases , one for each sign.

$c - 3 = 1 or - (c - 3) = 1$ $color(red)(c-3=1)" or "color(blue)(-(c-3)=1)$

$\Rightarrow c = 1 + 3 = 4 or - c + 3 = 1 thus c = 3 - 1 = 2$ $rArrcolor(red)(c=1+3=4)" or"color(blue)(-c+3=1)"thus "color(blue)(c=3-1=2)$

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How do you solve $| c - 3 | = 1$ $abs(c-3)=1$ ?

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How do you solve |c−3|=1abs(c-3)=1?

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How do you solve $| c - 3 | = 1$ $abs(c-3)=1$ ?