How do you solve $abs(8 - 6c ) = 1$ ?

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Answer 1 · 2017-02-19T11:42:46

$7/6<=c<=3/2$

The given equation is equivalent to:

$-1<=8-6c<=1$

Let's subtract 8 and get:

$-9<=-6c<=-7$

then change signs and inequality:

$7<=6c<=9$

and divide all terms by 6:

$7/6<=c<=cancel9^3/cancel6^2$

$7/6<=c<=3/2$

How do you solve abs(8 - 6c ) = 1 abs(8 - 6c ) = 1?