How do you solve $abs(7p+4)/8=3$ ?

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Answer 1 · 2016-09-03T12:33:01

p = -4 or p = # 20/7 Make the absolute value term both positive and negative and solve for p

The absolute value term can be either positive or negative in value as long as it equals $8 xx 3$

The goal is to isolate and solve for p so first multiply both sides by 8

First take the positive value of the absolute value term.

${+ ( 7p + 4) /8} xx 8 = 3 xx 8$ This gives

7p + 4  = 24       Subtract 4 from both sides

7p + 4 - 4 = 24 - 4 This gives

7p = 20 Divide both sides by 7

$7p/7$ = $20/7$ This gives p = $20/7$

Now take the negative value of the absolute value term.

${ -( 7p +4) / 8) xx 8 = 3 xx 8$ This gives

-7p = 28 divide both sides by -7

$-7 p/-7 = 28/-7$ This gives

p = -4

How do you solve abs(7p+4)/8=3abs(7p+4)/8=3?