How do you solve $abs(7+p)=7$ ?

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Answer 1 · 2016-09-19T11:33:15

$p=0"; "p=-14$

The sum inside the 'absolute' must be $+-7$
as $abs(+-7)=+7$

Thus $7+p=+-7$

Consider $" "7+p=+7 => p=0$

Consider $" "7+p=-7 => p=-14$

How do you solve abs(7+p)=7abs(7+p)=7?