How do you solve #abs(5x)+5=45#?
1 Answer
Feb 1, 2017
Explanation:
#"equations involving the" color(blue)" absolute value"# have 2 possible solutions.Isolate the absolute value.
subtract 5 from both sides of the equation.
#|5x|cancel(+5)cancel(-5)=45-5#
#rArr|5x|=40# The 2 solutions are obtained by solving
#5x=color(red)(+-)40#
#color(blue)"Solution 1"#
#"solve "5x=40rArrx=8#
#color(blue)"Solution 2"#
#"solve "5x=-40rArrx=-8#
#color(blue)"As a check"# Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
#x=8to|5xx8|+5=|40|+5=40+5 =45 color(white)(xx) ✔︎#
#x=-8to|5xx-8|+5=|-40|+5=40+5=45#
#rArrx=+-8" are the solutions"#
